Asymptotic & Maximum Likelihood Estimation cover

Asymptotic & Maximum Likelihood Estimation

2026-07-21T18:18:00.000Z# Statistics

Review

  1. Score function: Sθ(X)=∇θl(θ,X)S_\theta(X) = \nabla_\theta l(\theta, X)
    1. Local sufficient statistics: pθ0+η(X)pθ0(X)≈exp⁡{ηTSθ0(X)}\frac{p_{\theta_0+\eta}(X)}{p_{\theta_0}(X)} \approx \exp\{\eta^TS_{\theta_0}(X)\}
    2. Statistic property: E[Sθ(X)]=∫Sθ(x)dPθ(x)=∫Sθ(x)pθ(x) dμ(x)=∇θ∫pθ(x) dμ(x)=∇θEθ[X]=0\begin{aligned} \mathbb{E}[S_\theta(X)] &= \int S_\theta(x) dP_\theta(x) \\ &= \int S_\theta(x)p_\theta(x)\,d\mu(x) \\ &= \nabla_\theta \int p_\theta(x)\,d\mu(x) \\ &= \nabla_\theta\mathbb{E}_\theta[X] = 0 \end{aligned} Notation: This property holds true in any direction (any dimension of θ\theta)
  2. Fisher Information: J(θ)=Varθ(Sθ(X))=Eθ[−∇2l(θ;X)]J(\theta) = Var_\theta(S_\theta(X)) = \mathbb{E}_\theta[-\nabla^2l(\theta; X)] E[∇θl(θ,X)]=0⟹0=∂∂θj∂∂θiE[el]=∫(∂2l∂θj∂θi+∂l∂θj∂l∂θiel) dμ=Eθ[∇2l]+Eθ[SST]⟹Eθ[SST]=−Eθ[∇2l]\begin{aligned} & \mathbb{E}[\nabla_\theta l(\theta, X)] = 0 \\ \Longrightarrow 0 &= \dfrac{\partial}{\partial \theta_j}\dfrac{\partial}{\partial \theta_i}\mathbb{E}[e^l] \\ &= \int \left(\dfrac{\partial^2l}{\partial\theta_j\partial\theta_i} + \dfrac{\partial l}{\partial \theta_j}\dfrac{\partial l}{\partial\theta_i}e^l\right) \,d\mu \\ &= \mathbb{E}_\theta[\nabla^2l] + \mathbb{E}_\theta[SS^T] \\ \Longrightarrow \mathbb{E}_\theta[SS^T] &= -\mathbb{E}_\theta[\nabla^2l] \end{aligned}
    1. J(θ)=Var(Sθ)J(\theta) = Var(S_\theta)
    2. J(θ)=−E[∇2l]J(\theta) = -\mathbb{E}[\nabla^2l]

Asymptotic

2 kinds of convergence:

  1. cvg. in probability cip to constant c∈Rdc\in\mathbb{R}^d if P(∣∣Xn−c∣∣>ϵ)→0,∀ϵ>0\mathbb{P}(||X_n-c||>\epsilon)\rightarrow 0, \forall \epsilon>0
  2. cvg. in distribution cid to random variable XX if Ef(Xn)⟶Ef(X)\mathbb{E}f(X_n)\longrightarrow\mathbb{E}f(X) for all bdd,cts f:x→Rf: x\rightarrow\mathbb{R}

Limit Theorems

Let X1,X2,…∼iidXX_1, X_2, \dots \overset{iid}{\sim} X be random vectors, Xnˉ=1n∑i=1nXi\bar{X_n} = \dfrac{1}{n}\sum_{i=1}^{n}X_i,

  1. LLN: If E∣X∣<∞\mathbb{E}|X| < \infty, E[X]=μ\mathbb{E}[X] = \mu, then:
    1. Xnˉ⟶pμ\bar{X_n} \overset{p}{\longrightarrow}\mu (Xnˉ⟶a.s.μ\bar{X_n}\overset{a.s.}{\longrightarrow}\mu)
  2. CLT: If E[X]=μ∈Rd\mathbb{E}[X] = \mu \in \mathbb{R}^d, Var(X)=ΣVar(X) = \Sigma, then:
    1. n(Xnˉ−μ)⟶dN(0,Σ)\sqrt{n} (\bar{X_n}-\mu) \overset{d}{\longrightarrow} N(0, \Sigma)

Continuous Mapping

gg cts, X1,X2,…X_1, X_2, \dots r.v.s

  • If Xn⟶dXX_n \overset{d}{\longrightarrow}X, then g(Xn)⟶dg(X)g(X_n)\overset{d}{\longrightarrow}g(X)
  • If Xn⟶pcX_n \overset{p}{\longrightarrow}c, then g(Xn)⟶pg(c)g(X_n)\overset{p}{\longrightarrow}g(c)

Delta Method

If

{n(Xn−μ)⟶dN(0,σ2)f(x) differentiable at x=μ\begin{cases} \sqrt{n}(X_n-\mu)\overset{d}{\longrightarrow}N(0, \sigma^2) \\ f(x)\text{ differentiable at }x=\mu \end{cases}

Then n(f(Xn)−f(μ))⟶dN(0,f˙(μ)2σ2)\sqrt{n}(f(X_n)-f(\mu))\overset{d}{\longrightarrow}N(0, \dot{f}(\mu)^2\sigma^2) ( i.e. Xn≈N(μ,σ2/n)⟶df(Xn)≈N(f(μ),f˙(μ)σ2/n)X_n\approx N(\mu, \sigma^2/n) \overset{d}{\longrightarrow} f(X_n)\approx N(f(\mu), \dot{f}(\mu)\sigma^2/n) )

Maximum Likelihood Estimation

Setup:

  1. Given: X1,…,Xn∼iidPθ0X_1, \dots, X_n \overset{iid}{\sim}P_{\theta_0}
  2. Model: pθ(x),θ∈Θp_\theta(x), \theta\in\Theta
  3. Log likelihood: ln(θ)=∑i=1nlog⁡pθ(Xi)l_n(\theta)=\sum_{i=1}^{n}\log p_\theta(X_i)
  4. MLE: θ^n∈argmax⁡θ∈Θln(θ)\hat{\theta}_n \in \operatorname{arg max}_{\theta\in\Theta}l_n(\theta)
  5. Problem: θ^n⟶θ0?\hat{\theta}_n \longrightarrow \theta_0 ?, n(θ^n−θ0)⟶?\sqrt{n}(\hat{\theta}_n - \theta_0) \longrightarrow ?

MLE

Consistency of MLE

θ^n→pθ0\hat{\theta}_n \overset{p}{\rightarrow}\theta_0 if θ^n∈argmax⁡θ∈Θln(θ;X)\hat{\theta}_n \in \operatorname*{arg max}_{\theta\in\Theta}l_n(\theta; X)

proof sketch:

Wi(θ)=l(θ;Xi)−l(θ0;Xi)Wˉn=1n∑Wiμ(θ)=E[Wi]=−DKL(θ0∣∣θ)δn=∣Wˉn(θ)−μ(θ)∣\begin{gather} W_i(\theta) = l(\theta; X_i) - l(\theta_0; X_i) \\ \bar{W}_n = \dfrac{1}{n}\sum W_i \\ \mu(\theta) = \mathbb{E}[W_i] = -D_{KL}(\theta_0 ||\theta) \\ \delta_n = |\bar{W}_n(\theta) - \mu(\theta)| \end{gather} {θ^n∈Θϵ}⊂{Wˉn(θ0)<Wˉn(θ^nϵ)}\{\hat{\theta}_n \in \Theta_\epsilon\} \subset \{\bar{W}_n(\theta_0)<\bar{W}_n(\hat{\theta}_n^\epsilon)\} ⟹P(θ^n∈Θϵ)<P(Wˉn(θ0)<Wˉn(θ^nϵ))⟹P({θ^n∈Θϵ})<P(−δn<μ(θ^nϵ)+δn)\begin{gather} \Longrightarrow P(\hat{\theta}_n \in \Theta_\epsilon) < P(\bar{W}_n(\theta_0)<\bar{W}_n(\hat{\theta}_n^\epsilon)) \\ \Longrightarrow P(\{\hat{\theta}_n \in \Theta_\epsilon\}) < P(-\delta_n<\mu(\hat{\theta}_n^\epsilon)+\delta_n) \end{gather}

moreover:

δn⟶p0μ(θ^nϵ)<0\begin{gather} \delta_n\overset{p}{\longrightarrow}0 \\ \mu(\hat{\theta}_n^\epsilon) < 0 \end{gather}

thus:

P({θ^n∈Θϵ})⟶p0P(\{\hat{\theta}_n \in \Theta_\epsilon\}) \overset{p}{\longrightarrow} 0

Asymptotic Distribution of MLE

σn(θ^n−θ0)⇒N(0,J1(θ0)−1)\sigma_n(\hat{\theta}_n-\theta_0)\Rightarrow N(0, J_1(\theta_0)^{-1})